丨x-1丨+（y+2）²=0
∴x-1=0
y+2=0
∴x=1
y=-2
5x²y-[2x²y-3(xy²-2x²y+2xy²)]
=5x²y-2x²y+3xy²-6x²y+6xy²
=-3x²y+9xy²
=6+36
=42
5x²y-[2x²y-3(xy²-2x²y+2xy²)],其中x,y满
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