Question

已知函数y=x^2-2x-3在t

Answer 1

对称轴x=1,顶点(1,-4)

(1)

t+1≤1即t≤0时

y=f(x)在[t,t+1]单调递减

g(t)=f(t)=t²-2t-3

h(t)=f(t+1)=t²-4

(2)

t≥1时

y=f(x)在[t,t+1]单调递增

g(t)=f(t+1)=t²-4

h(t)=f(t)=t²-2t-3

(3)

t1即0