(2013•建邺区一模)化简:(xx+1+1x−1)÷x2+1x2+x−1x−1.
1个回答
原式=
x(x−1)+x+1
(x+1)(x−1)•
x(x+1)
x2+1-[1/x−1]=[x/x−1]-[1/x−1]=1.
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