Question

已知a是最小正整数,b,c是有理数,并且|a+b|+(3a+2c）^2=0求式子

Answer 1

-22/21 【占个位先

∵a是最小正整数

∴a=1

∵|a+b|+(3a+2c）^2=0

∴a+b=0 3a+2c=0

∴b=-1

3+2c=0

c=-1.5

(4ab+c)/(-a²+c²+4)

=(-4-1.5)/(-1+2.25+4)

=-5.5/5.25

=-22/21