有对数换底公式：log(m)n=lgn/lgm.
所以logN=log(3)6+log(4)12-log(2)9
=lg6/lg3+lg12/lg4-lg9/lg2
=(lg2+lg3)/lg3+(lg3+2lg2)/2lg2-2lg3/lg2
=lg2/lg3+1+1/2*(lg3/lg2)+1-2lg3/lg2
=2+lg2/lg3-3/2*(lg3/lg2)
[=2+log(3)2-3/2*log(2)3]
只能化到这里最简了.
logN=log(3)6+log(4)12-log(2)9
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