前两题通分,后一题计算,最后一题化简

1个回答

  • a(x-y)分之x,b(y-x)分之y

    公分母ab(x-y)

    所以x/a(x-y)=bx/ab(x-y)

    y/b(y-x)=-ay/ab(x-y)

    (2-x)的平方分之1,(x+2)(x-2)分之x

    (2-x)²=(x-2)²

    所以公分母(x-2)²(x+2)

    所以1/(2-x)²=(x+2)/(x-2)²(x+2)

    x/(x+2)(x-2)=(x²-2x)/(x-2)²(x+2)

    计算:(x的平方-4x+3分之x的平方-4)的平方乘(x的平方+3x+2分之x-3)除以(-x的平方-1分之x-2)

    =[(x+2)(x-2)/(x-1)(x-3)]²*[(x-3)/(x+1)(x+2)]*(-x²-1)/(x-2)

    =(-x²-1)(x+2)²(x-2)²(x-3)/[(x-1)²(x-3)²(x+1)(x+2)(x-2)]

    =(-x²-1)(x+2)(x-2)/[(x-1)²(x-3)(x+1)]

    化简a+2分之a的平方-4除以(a-2)乘以a-2分之1

    =[(a+2)(a-2)/(a+2)]÷(a-2)*1/(a-2)

    =(a-2)/(a-2)²

    =1/(a-2)