M + 2 HCl= MCl2 + H2 (向上箭头)
X .2
5.6 .0.19
X = 58.9
即,铁片(假设均为2价)中,铁的摩尔质量56小于58.9,则杂质的摩尔质量大于58.9,即,两个组分中至少有一个大于58.9
A.铝27*3/2 (将铝化为2价) < 58.9 铅 82>58.9
B.镁24 < 58.9 锌65>58.9
C.锌65>58.9 铜64>58.9
D.镁24 < 58.9 铝27*3/2< 58.9
所以选D
M + 2 HCl= MCl2 + H2 (向上箭头)
X .2
5.6 .0.19
X = 58.9
即,铁片(假设均为2价)中,铁的摩尔质量56小于58.9,则杂质的摩尔质量大于58.9,即,两个组分中至少有一个大于58.9
A.铝27*3/2 (将铝化为2价) < 58.9 铅 82>58.9
B.镁24 < 58.9 锌65>58.9
C.锌65>58.9 铜64>58.9
D.镁24 < 58.9 铝27*3/2< 58.9
所以选D