A=3x²-2x-1 B=x²-4x+7 C=x²-3x+6
A=(3x+1)(x-1)
(1)原式=(3x²-2x-1)[(x²-4x+7)-(x²-3x+6)]=(3x²-2x-1)(-x+1)=3x³+2x²+x+3x²-2x-1
=3x³+5x²-x-1
(2)原式=(3x²-2x-1)/[(x²-3x+6)-(x²-4x+7)]=(3x²-2x-1)/(x-1)=(3x+1)(x-1)/(x-1)
=3x+1
A=3x²-2x-1 B=x²-4x+7 C=x²-3x+6
A=(3x+1)(x-1)
(1)原式=(3x²-2x-1)[(x²-4x+7)-(x²-3x+6)]=(3x²-2x-1)(-x+1)=3x³+2x²+x+3x²-2x-1
=3x³+5x²-x-1
(2)原式=(3x²-2x-1)/[(x²-3x+6)-(x²-4x+7)]=(3x²-2x-1)/(x-1)=(3x+1)(x-1)/(x-1)
=3x+1