如图,电源电压不变.只闭合S1,电流为I1,R1功率为P1,R3功率4w;只闭合S2,电流为I2,R3功率P2

2个回答

  • 只闭合S1,R1与R3串联.

    I1=U/(R1+R3) ①

    P1=I1²R1= U²R1/(R1+R3)² ②

    P3=I1²R3=4W ③

    只闭合S2,R2与R3串联.

    I2=U/(R2+R3) ④

    P2=I2²R3= U²R3/(R2+R3)² ⑤

    由②得:R1=P1/I1²

    由⑤得:R3=P2/I2²

    已知:P1:P2=4:9,I1:I2=2:3

    得:R1=R3 ⑥

    综合②③⑥式得:P1=P3=4W

    P1=U²R1/(R1+R3)²=U²/4R1=4W

    U²=16R1 ⑦

    P1:P2=4:9 P1=4W

    P2=9W

    综合⑤⑥⑦式得:P2=U²R3/(R2+R3)²=16R1²/(R2+R1)²=9W

    4R1=3(R2+R1)

    R1=3R2 ⑧

    开关S1,S2,S3,都闭合时,R1与R2并联.

    P总=P1‘+P2'=U²/R1 + U²/R2=16R1/R1 + 16R1/(R1/3)=16+48=64W