(2x-a)*(3x+b)
=6x²+(2b-3a)-ab
=6x²+11x-10
∴2b-3a=11
(2x-a)*(x+b)
=2x²+(2b+a)x+ab
=2x²-9x-10
∴2b+a=-9 ①
∵2b-3a=11 ②
②-①得出,a=-5,b=-2
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