1.原式=[x+(2y+3z)][x-(2y+3z)]
=x²-(2y+3z)²
=x²-4y²-12yz-9z²
2 .原式=(x²/4+3xy+9y²-y²/4-xy-x²+9x²-3xy+y²/4-9y²+x²/4)÷(x/2)
=(17x²/2-xy)÷(x/2)
=17x²/2÷(x/2)-xy÷(x/2)
=17x-2y
计算：1.(-x+2y+3z)(x-2y-3z) 2.[(x/2+3y)^2-(y/2+x)^2+(3x-2/y)^2-
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