a2+a8=2a5=22,则:a5=11
所以a2=5,则:
3d=a5-a2=6,d=2
a1=3
an=a1+(n-1)d=2n+1
数列{bn}的前n项和,设为Bn,则:Bn=2n+1
则:bn=Bn-B(n-1)=2
则:cn=(bn)×n=2n
Sn=[n(c1+cn)]/2=n²+n
a2+a8=2a5=22,则:a5=11
所以a2=5,则:
3d=a5-a2=6,d=2
a1=3
an=a1+(n-1)d=2n+1
数列{bn}的前n项和,设为Bn,则:Bn=2n+1
则:bn=Bn-B(n-1)=2
则:cn=(bn)×n=2n
Sn=[n(c1+cn)]/2=n²+n