灯L 1:
R 1 =
U 2额1
P 额1 =
(6V) 2
3W =12Ω
灯L 1正常发光电流: I 1 =
P 额1
U 额1 =
3W
6V =0.5A
灯L 2:
R 2 =
U 2额2
P 额2 =
(6V) 2
6W =6Ω
灯L 2正常发光电流: I 2 =
P 额2
U 额2 =
6W
6V =1A
根据题意可知电路中的电流:I=0.5A
∴U=I(R 1+R 2)=0.5A×(12Ω+6Ω)=9V
P=UI=9V×0.5A=4.5W
故答案为:9;4.5.
灯L 1:
R 1 =
U 2额1
P 额1 =
(6V) 2
3W =12Ω
灯L 1正常发光电流: I 1 =
P 额1
U 额1 =
3W
6V =0.5A
灯L 2:
R 2 =
U 2额2
P 额2 =
(6V) 2
6W =6Ω
灯L 2正常发光电流: I 2 =
P 额2
U 额2 =
6W
6V =1A
根据题意可知电路中的电流:I=0.5A
∴U=I(R 1+R 2)=0.5A×(12Ω+6Ω)=9V
P=UI=9V×0.5A=4.5W
故答案为:9;4.5.