令 G(x) = x * f(x) ,G(x)在【0,1】上连续,(0,1)可导,且 G(0) = G(1) = 0
G(x)在【0,1】上满足罗尔中值定理,至少存在一点 m ∈(0,1),使得 G'(m) = 0
即有 m * f '(m) + f(m) = 0 成立.
令 G(x) = x * f(x) ,G(x)在【0,1】上连续,(0,1)可导,且 G(0) = G(1) = 0
G(x)在【0,1】上满足罗尔中值定理,至少存在一点 m ∈(0,1),使得 G'(m) = 0
即有 m * f '(m) + f(m) = 0 成立.