Question

已知x＾m＝2,x＾n=3（m,n是正整数）.求：（1）x＾2m+3n；（2）x＾2m+x＾3n

Answer 1

（1）

x^(2m+3n)

=x^(2m)*x^(3n)

=(x^m)^2*(x^n)^3

=2^2*3^3

=4*27

=108

(2)

x＾2m+x＾3n

=x^(2m)+x^(3n)

=(x^m)^2+(x^n)^3

=2^2+3^3

=4+27

=31