你算错了.X平方项等式两边化掉了.最后算出X=2
3x(7-2x)+5x(2x-1)=4x(x-3)+56
3个回答
相关问题
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解方程 3x(7-2x)+5x(2x-1)=4x(x-3)+56
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解方程：3x（7-2x）+5x（2x-1）=4x（x-3）+56．
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用线性代数解x1+3x2+5x3+7x4 =12,3x1+5x2+7x3+x4=0,5x1+7x2+x3+3x4=1,7
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x1 + x2 + x3 + x4 + x5 = 7 4x1 + 2x2 + 3x3 + 2x4 - 2x5 = 5 x
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(4.5-x)*7=17.5 x/2+4=3/2x+1 7/2*2/3-4x=7/3 5/8(x-.3)=75% 1+x
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X1 - X3 - X4 -5X5=0 X1+2X2+3X3+3X4+7X5=0 X1+X2+X3+X4+X5=0 X2
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x-1/4X=5/12X-3/8X=3/56X+3/2X=15
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(x+1)(x+2)(x+3)(x+4)-(x^2+5x+3)(x^2+5x+7)=?
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3x+7=4x+5,4x-6=-3+5x,2x+1-x=3-3x,3x-1=x,3x-2=5x-6,4x+5=3x+3-