2x+5y+5x+2y=16+19
7x+7y=35
7(x+y)=35
结论一:x+y=5
(2x+5y)-(5x+2y)=16-19
(2x-5x)+(5y-2y)=-3
3y-3x=-3
3(y-x)=-3
y-x=-1
结论二:y=x-1
x+y=5 ,y=x-1
x+(x-1)=5
zx-1=5
x=3,
y=x-1
y=2
2x+5y+5x+2y=16+19
7x+7y=35
7(x+y)=35
结论一:x+y=5
(2x+5y)-(5x+2y)=16-19
(2x-5x)+(5y-2y)=-3
3y-3x=-3
3(y-x)=-3
y-x=-1
结论二:y=x-1
x+y=5 ,y=x-1
x+(x-1)=5
zx-1=5
x=3,
y=x-1
y=2