已知函数f(x)=2sin^2x+2倍根号3sinxcosx+a(a属于R)

1个回答

  • f(x) = 2sin^2x+2根号3sinxcosx+a = 1-cos2x+根号3sin2x+a

    = 2(根号3/2 sin2x - 1/2 cos2x) + a-1 = 2( sin2xcosπ/6 - cos2xsinπ/6) + a-1

    = 2sin(2x-π/6) + a-1 = 2sin2(x-π/12) + a-1

    (1)

    当2kπ-π/2<2(x-π/12)<2kπ+π/2,即kπ-π/6<x<kπ+π/3,k∈Z时,单调增

    对称中心:(π/12,a-1)

    (2)

    x∈[0,π/2]时,在(0,π/3)单调增,在(π/3,π/2)单调减

    f(0)=2sin(0-π/6) + a-1 =-1+a-1=a-2

    f(π/2)=2sin(π-π/6) + a-1 =1+a-1=a

    f(0)<f(π/2)

    最小值f(0)=a-2=3,a=5

    (3)

    若a=-1

    f(x)=2sin2(x-π/12) -1-1 = 2sin2(x-π/12) -2

    将函数图像左移π/12个单位,上移2个单位,将得到一个奇函数:

    f(x)= 2sin2x