十字相乘法,原式化成(a-4)(a+2)=0就可以得到满足的解,a=4或a=-2,代入1/a+1－a+3/a²－1·a²－2a+1/(a+1)(a+3)就行,不用多说了吧
已知实数a满足a²+2a－8=0,求1/a+1－a+3/a²－1·a²－2a+1/(a+1)(a+3)的值.
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