因为 x/y=1/2 所以 x=y/2 y=2x
所以:
(x^2+2xy+y^2)/ (X^2-xy-2 y^2)
=(x+y)(x+y)/(x+y)(x-2y)
=(x+y)/(x-2y)
把 y=2x 代进 (x+y)/(x-2y)
则:
(x+y)/(x-2y)
=(x+2x)/(x-4x)
=3x/(-3x)
=-3/3
=-1
因为 x/y=1/2 所以 x=y/2 y=2x
所以:
(x^2+2xy+y^2)/ (X^2-xy-2 y^2)
=(x+y)(x+y)/(x+y)(x-2y)
=(x+y)/(x-2y)
把 y=2x 代进 (x+y)/(x-2y)
则:
(x+y)/(x-2y)
=(x+2x)/(x-4x)
=3x/(-3x)
=-3/3
=-1