Question

（x+2/x+1）-（x+4/x+3）=（x+6/x+5）-（x+8/x+7）求过程

Answer 1

1+1/x+1-1-1/x-3=1+1/x+5-1- 1/x+7

1/x+1-1/x+3-1/x+5+1/x+7=0

( x+3-x-1)/(x+1)(x+3)=(x+7-x-5)/(x+5)(x+7)

( x+1)(x+3)=(x+5)(x+7)

x^2+4x+3=x^2+12x+35

8x=-32

x=-4