分式的加减1.(x-3)/(x^2-1)-2/(1+x)2.2x+2+5/(x-1)3.x/(x^2-25)-5/(x^

1个回答

  • 1.(x-3)/(x^2-1)-2/(1+x)

    =(x-3)/(x+1)(x-1)-2(x-1)/(x+1)(x-1)

    =(x-3-2x+2)/(x+1)(x-1)

    =(-x-1)/(x+1)(x-1)

    =-(x+1)/(x+1)(x-1)

    =-1/(x-1)

    2.2x+2+5/(x-1)

    =[2(x+1)(x-1)+5]/(x-1)

    =(2x^2-2+5)/(x-1)

    =(2x^2+3)/(x-1)

    3.x/(x^2-25)-5/(x^2+10x+25)

    =x/(x+5)(x-5)-5/(x+5)^2

    =[x(x+5)-5(x-5)]/(x+5)^2(x-5)

    =(x^2+5x-5x+25)/(x+5)^2(x-5)

    =(x^2+25)/(x+5)^2(x-5)

    4.2xy/(x^2-y^2)+x/(x+y)-y/(y-x)

    =2xy/(x+y)(x-y)+x(x-y)/(x+y)(x-y)+y(x+y)/(x+y)(x-y)

    =(2xy+x^2-xy+xy+y^2)/(x+y)(x-y)

    =(x^2+y^2+2xy)/(x+y)(x-y)

    =(x+y)^2/(x+y)(x-y)

    =(x+y)/(x-y)

    5.(a-1)/a/(a-1/a)

    =[(a-1)/a]/(a^2-1)/a]

    =(a-1)/(a+1)(a-1)

    =1/(a+1)

    =1/(2+1)

    =1/3