已知x分之1-y分之1=5,
2x+7xy-2y分之-x+xy+y
=(-x+xy+y)/(2x+7xy-2y)
=(-1/y+1+1/x)/(2/y+7-2/x)
=(5+1)/(7-10)
=6/(-3)
=-2;
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已知x分之1-y分之1=5,
2x+7xy-2y分之-x+xy+y
=(-x+xy+y)/(2x+7xy-2y)
=(-1/y+1+1/x)/(2/y+7-2/x)
=(5+1)/(7-10)
=6/(-3)
=-2;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,