Question

在△ABC中,角A B C所对的边分别是a b c,已知√3c=2asinC,且A为锐角

Answer 1

1、√3c=2asinC

C/sinC=a/（√3/2）,根据正弦定理C/sinC=a/sinA,得sinA=√3/2,A=π/3

2、将AB=2√3,BC=3代入√3c=2asinC得出√3*2√3=2*3*sin,得sinc=1,C=π/2

B=π-π/2-π/3=π/6.面积=1/2*AB*BC*sinB=3√3/2