2xy^2＋x^2y－xy＝xy( )

1个回答

x2+2xy+y2x2y+xy2−x2−2xy+y2x2y−xy2．
((xy+2)(xy-2)-2x²y²+5(xy-y)²)÷(2xy)
3x2y−[2xy2−2(xy−32x2y)+xy]+3xy2．
5xy^2-(3xy^2-(4xy^2-2x^2y))+2x^2y-xy^2
((xy+2)(xy-2)-2(X^2y^2-2))/(xy)=
(5x²y-2xy²-3xy)-(2xy+5x²y-2xy²),x=-1/5,y
(3xy-9x2-2y2-6xy)-(6x2+2xy-3xy-y)
已知x²+2xy+y²\xy-y²÷A=xy+y²\x²-2xy+y&
[(x^2-2xy)+x^2]/(y^2+2xy)-(x^2+2xy)
【xy(x²-3y)+3xy²】(-2xy)+x³y²(2x-y)