(m^2+4m)^2+8(m^2+4m)+16

1个回答

  • 初一数学因式分解

    1.(m^2+4m)^2+8(m^2+4m)+16

    解,得:

    ==[(m^2+4m)+4]^2

    ==(m^2+4m+4)^2

    ==(m+2)^4

    2.(3a-5b)^2-(5a-3b〉^2

    解,得:

    ==[(3a-5b)+(5a-3b)]*[(3a-5b)-(5a-3b)]

    ==(8a-8b)*(-2a-2b)

    ==-16(a-b)*(a+b)

    3.4a^2-16a^4

    解,得:

    ==4a^2(1-4a^2)

    ==4a^2(1+2a)(1-2a)

    4.4a^2-(a^2+1)^2

    解,得:

    ==[2a+(a^2+1)]*[ 2a-(a^2+1) ]

    ==(2a+a^2+1)*(2a-a^2-1)

    ==-(a+1)^2(a-1)^2

    5.9x^2-y^2-6x+1

    解,得:

    == (9x^2-6x+1)-y^2

    ==(3x-1)^2-y^2

    ==(3x-1+y)(3x-1-y)