过D作DF⊥AB于F,
∵DE⊥AC,AD平分∠CAB,
∴DE=DF=2,
∴SΔABC=SΔABD+SΔACD
=1/2AB×DF+1/2AC*DE
=1/2×4×2+1/2×6×2
=10平方厘米.