设C(x,0)
AB^2=6^2+2^2=40
AC^2=x^2+2^2=x^2+4
BC^2=(6-x)^2+4^2=x^2-12x+52
AB=AC得x=6(-6舍弃)
AB=BC得x^2-12x+12=0 x=6+3根号3 x=6-3根号3
AC=BC得12x=48 x=4
设C(x,0)
AB^2=6^2+2^2=40
AC^2=x^2+2^2=x^2+4
BC^2=(6-x)^2+4^2=x^2-12x+52
AB=AC得x=6(-6舍弃)
AB=BC得x^2-12x+12=0 x=6+3根号3 x=6-3根号3
AC=BC得12x=48 x=4