y=(m-2)x^2-4x+m^2+2m-8
是二次函数,则m-2≠0,m≠2
把(0,0)代入,得:
m^2+2m-8=0
(m-2)(m+4)=0
m=2(舍去)或m=-4
函数解析式为:
y=(-4-2)x^2-4x+(-4)^2+2*(-4)-8
=-6x^2-4x
y=(m-2)x^2-4x+m^2+2m-8
是二次函数,则m-2≠0,m≠2
把(0,0)代入,得:
m^2+2m-8=0
(m-2)(m+4)=0
m=2(舍去)或m=-4
函数解析式为:
y=(-4-2)x^2-4x+(-4)^2+2*(-4)-8
=-6x^2-4x