Question

三角形的三条边分别为x,y,z.

Answer 1

x^2 +y^2 +z^2 -6x-8y-10z+50=0

[x^2-6x+9]+[y^2-8y+16]+[z^2-10z+25]=0

[x-3]^2+[y-4]^2+[z-5]^2=0

x-3=0===>x=3

y-4=0===>y=4

z-5=0===>z=5

3^2+4^4=5^2

所以三角形是直角三角形