已知x+y=6,xy=4,x>y则√x-√y/√x+√y

2个回答

  • √x-√y/√x+√y

    =(√x-√y)(√x+√y)/(√x+√y)²

    =(x-y)/(x+y+2√xy)

    =(x-y)/(6+2√4)

    =(x-y)/10

    x>y,x-y=√(x-y)²=√[(x+y)²-4xy]=√(6²-16)=√20=2√5

    ∴√x-√y/√x+√y=2√5/10=√5/5

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