|x-z-3|+(2x-4y-7)^2+(3x+4y-13)^2=0
x-z-3=0(1)
2x-4y-7=0(2)
3x+4y-13=0(3)
(3)+(1)得:5x=20
x=4
则y=1/4
z=1
x^3z= 4^3=64 y^3z+1=(1/4)^4=1/256
|x-z-3|+(2x-4y-7)^2+(3x+4y-13)^2=0
x-z-3=0(1)
2x-4y-7=0(2)
3x+4y-13=0(3)
(3)+(1)得:5x=20
x=4
则y=1/4
z=1
x^3z= 4^3=64 y^3z+1=(1/4)^4=1/256