若1/m-1/n=3,求2m-3mn-2n/m-2mn-m的值

2个回答

  • (1)是(2m-3mn-2n)/(m-2mn-n)吧?

    1/m-1/n=3

    (n-m)/mn=3

    n-m=3mn

    (2m-3mn-2n)/(m-2mn-n)

    =[2(m-n)-3mn]/[(m-n)-2mn]

    =(-6mn-3mn)/(-3mn-2mn)

    =9mn/5mn

    =9/5

    (2)

    x+3y+7z=0

    3x-4y-18z=0

    解方程组:

    y=-3x/2

    z=x/2

    (3x^2+5y^2+6z^2)/(x^2+2y^2+8z^2)

    =[3x^2+5*(-3x/2)^2+6(x/2)^2]/[x^2+2(-3x/2)^2+8(x/2)^2]

    =(3x^2+45x^2/4+3x^2/2)/(x^2+9x^2/2+2x^2)

    =(3+45/4+3/2)/(1+9/2+2)

    =(12+45+6)/(4+18+8)

    =63/30

    =21/10

    (3)

    1/x-1/y=3

    (y-x)/xy=3

    y-x=3xy

    (2x+3xy-2y)/(x-2xy-y)

    =[3xy-2(y-x)]/[(x-y)-2xy]

    =(3xy-6xy)/(-3xy-2xy)

    =3xy/5xy

    =3/5