Question

一个0.1kg的木块放在一块0.9kg的木板上,一初速度为19m/s运动,已知木块与木板的摩擦因素0.2,

Answer 1

当v1=v2,19-a1t=a2t

a1=0.1*10*0.2=2

a2=(0.1+0.9)*10*0.01/9=1/9

联立T=9

s=1/2at^2=4.5