Question

求证 y^log x=x^ log y

Answer 1

求证 y^log x=x^ log y

设：y^log x=z1；x^ log y=z2

log(y) z1=log x；log(x) z2=log y

log(y) z1=log z1/log y=log x；log(x) z2=log z2/log x=log y

log z1=(log x)*(log y)；log z2=(log x)*(log y)

所以：log z1=log z2

z1=z2

y^log x=x^ log y