∵方程x 2-(7n+6)x+2(n+1)(5n+4)=0变形为(x-2n-2)(x-5n-4)=0,
则整数根即为2n+2或5n+4.
又抛物线与x轴的两个交点的横坐标的差的平方等于
b 2 -4ac
a 2 =4n 2+3n+2,
①当4n 2+3n+2=2n+2时,解得n=0或n=-
1
4 (应舍去);
②当4n 2+3n+2=5n+4时,解得n=1或-
1
2 (应舍去).
则n=1或0.
∵方程x 2-(7n+6)x+2(n+1)(5n+4)=0变形为(x-2n-2)(x-5n-4)=0,
则整数根即为2n+2或5n+4.
又抛物线与x轴的两个交点的横坐标的差的平方等于
b 2 -4ac
a 2 =4n 2+3n+2,
①当4n 2+3n+2=2n+2时,解得n=0或n=-
1
4 (应舍去);
②当4n 2+3n+2=5n+4时,解得n=1或-
1
2 (应舍去).
则n=1或0.