AC+CE=AE=8.9cm
BC+CD=BD=3cm
AB+DE=AE-BD=8.9-3=5.9
AD+BE=AB+BD+BD+DE=AB+DE+2BD=5.9+2*3=11.9
即以A,B,C,D,E五点为端点的所有线段的和:
AB+AC+AD+AE+BC+BD+BE+CD+CE+DE
=(AB+DE)+(AC+CE)+(AD+BE)+AE+(BC+CD)+BD
=5.9+8.9+11.9+8.9+3+3
=41.6
AC+CE=AE=8.9cm
BC+CD=BD=3cm
AB+DE=AE-BD=8.9-3=5.9
AD+BE=AB+BD+BD+DE=AB+DE+2BD=5.9+2*3=11.9
即以A,B,C,D,E五点为端点的所有线段的和:
AB+AC+AD+AE+BC+BD+BE+CD+CE+DE
=(AB+DE)+(AC+CE)+(AD+BE)+AE+(BC+CD)+BD
=5.9+8.9+11.9+8.9+3+3
=41.6