设：(y+z)/a^2=(z+x)/b^2=(x+y)/c^2=t
可求x=t（b^2+c^2-a^2）/2 y= z=... 显然t不等于0代入
xy+yz+zx=0然后就化出来了
设：(y+z)/a^2=(z+x)/b^2=(x+y)/c^2,且xy+yz+zx=0,xyz≠0.求证：(a+b+c)
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