f^-1*(1/3)是f(1/3)的逆吗?
令t=2^x,x=log2(t)
y=t/(1+t)
t=y/(1-y)
x=log2[y/(1-y)]
即,f^[-1](x)=log2[x/(1-x)]
f^-1*(1/3)=log2[(1/3)/(2/3)]= -1
5.设f(x)=2^x/1+2^x,则f^-1*(1/3)=
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