Question

计算:(1)(b-a)/(a²-b²)=_____；(2)1/x - 1/(x+1)=_____.

Answer 1

(1)(b-a)/(a²-b²)

=(b-a)/(a+b)(a-b)

=-1/(a+b)

1/x - 1/(x+1)

=(x+1-x)/x(x+1)

=1/(x²+x)

如追加其它问题,