Question

帮我解解方程组：1式：7b+3a/2 = 22；2式：5a-6b/3 = 5

Answer 1

由（2）得

5a-2b=5

2b=5a-5

b=(5a-5)/2 (3)

把（3）代入（1）得

7(5a-5)/2+3a/2=22

7(5a-5)+3a=22*2

35a-35+3a=44

38a=79

a=79/38 代入（3）得

b=(5a-5)/2

b=(5*79/38-190/38)/2

b=205/38*1/2

b=205/76

故a=79/38,b=205/76