1.∵∏/4≤x≤∏/2,
∴∏/2≤2x≤∏,故∏/6≤2x-∏/3≤2∏/3
∴1/2≤sin(2x-∏/3)≤1
∴1≤2sin(2x-∏/3)≤2
∴2≤f(x)≤3.
2.2
已知函数f(x)=1+2sin(2x-π/3),x∈[π/4,π/2]
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