选D
原因如下:
S△ABO = 2 x 2 / 2 = 2
过B作BC⊥AO于C.
因为AO = 2根号5 所以BC = 2/(根号5) = 2*(根号5)/5
又BO = 2根号2
所以sin∠AOB = BC/BO = [2*(根号5)/5] / (2根号2) = (根号10)/10
选D
原因如下:
S△ABO = 2 x 2 / 2 = 2
过B作BC⊥AO于C.
因为AO = 2根号5 所以BC = 2/(根号5) = 2*(根号5)/5
又BO = 2根号2
所以sin∠AOB = BC/BO = [2*(根号5)/5] / (2根号2) = (根号10)/10