Question

整数指幂的运算：（1）(x^2+2xy+y^2/x^2-y^2)^-2 (2) (x^2-4y^2/(x^2-2xy)+

Answer 1

(1). 原式=[(x+y)^2/(x+y)(x-y)]^-2

=[(x+y)/(x-y)]^-2

=(x-y)^2/(x+y)^2

(2).原式={(x+2y)(x-2y)/[x(x-2y)+(x-2y)]}^-1

=[(x+2y)(x-2y)/(x+1)(x-2y)]^-1

=[(x+2y)/(x+1)]^-1

=(x+1)/(x+2y)