2007x+y=3011
x+2007y=1005
两式相加得
2008x+2008y=4016
2008(x+y)=4016
x+y=2
两式相减得
2006x-200y=2006
2006(x-y)=2006
x-y=1
(x+y)的平方+(x-y)的3次方
=2²+1³
=4+1
=5
2007x+y=3011
x+2007y=1005
两式相加得
2008x+2008y=4016
2008(x+y)=4016
x+y=2
两式相减得
2006x-200y=2006
2006(x-y)=2006
x-y=1
(x+y)的平方+(x-y)的3次方
=2²+1³
=4+1
=5