解
原式
=(x-y)[(x+y)²-xy+(x-y)²+xy]
=(x-y)[(x+y)²+(x-y)²]
=(x-y)(x²+2xy+y²+x²-2xy+y²)
=(x-y)(2x²+2y²)
=2(x-y)(x²+y²)
(x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy]
3个回答
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