高数3道极限4道导数,

1个回答

  • 三.

    1.

    原式=lim(x→无穷)(2+1/n+1/n^2)/(1/n^2+1-2/n)

    =lim(x→无穷)2/1=2

    4.

    lim(x→0)(1+x)^(2/x)

    =lim(x→0)(1+x)^(1/x)(2)

    =e^2

    6.

    lim(x→π/2)lnsinx/(π-2x)^2

    =lim(x→π/2)[cosx/sinx]/2(π-2x)(-2)

    =(-1/4)lim(x→π/2)[cotx]/(π-2x)

    =(-1/4)lim(x→π/2)[-csc^2x]/(-2)

    =(-1/4)lim(x→π/2)[-1]/(-2)

    =-1/8

    四.

    1.

    y=sinxlnx^2

    y'=cosxlnx^2+sinx(2/x)

    2.

    lny=cosxlna

    (1/y)y'=-sinxlna+cosx/a

    y'=(a^cosx)[-sinxlna+cosx/a]

    3.

    y=ln(x-cos3x)

    y'=[1/(x-cos3x)](1+3sin3x)

    4.

    y=3a^x+e^x-2/x

    y'=3a^xlna+e^x+2/x^2