计算(x-1)(x+1)(x2+1)(x4+1)
2个回答
(x-1)(x+1)(x2+1)(x4+1)
=(x2-1)(x2+1)(x4+1)
=(x4-1)(x4+1)
=x8-1
相关问题
初中分式计算计算1/(1-x)+1/(1+x)+2/(1+x^2)+4/(1+x^4)猜想1/(1-x)+1/(1+x)
分式计算:1/(1-x) -1/(1+x)-2x/(1+x^2)+(-4x^3)/(1+x^4)=?
计算1/(1+X)+1/(1-X)+1/(1+X2)+4/(1+X4)
计算:(x-2/x+2加上x/x^2-4)除以1/x^2-4 计算:1/x+1加上1/x-1 计算:a+1/a-1减去a
计算(x+1/x)(x2+1/x2)(x4+1/x4)…(x16+1/x16)(x2-1)
计算 (1-2X)(1+2X)(1+4X^2)(1+16X^4)
计算(2x-1)(2x+1)(4x²+1)
计算(2x-1)(4x²+1)(2x+1),
计算[x+(1)/x][x^2+(1)/x^2][x^4+(1)/x^4][x^8+(1)/x^8][x^16+(1)/
计算1/x(x+2)+1/(x+2)(x+4)+1/(x+4)(x+6)+...1/(x+2004)(x+2006)