将70gNa2O和Na2O2的混合物与98g水充分反应后,所得NaOH溶液溶质质量分数为50%,求混合物中Na2O和Na

1个回答

  • 设Na2O2为xmol,Na2O为ymol

    Na2O-----2NaOH 2Na2O2---4NaOH---O2

    1mol 2mol 2mol 4mol 1mol

    y 2ymol x 2x 1/2x

    m(O2)=1/2x*32g/mol

    m液=70g+98g-16x=(168-16x)g

    m(NaOH)=(2x+2y)*40g

    m(NaOH)/m液=50%化简得 62y+78x=70 88x+80y=84

    x=0.5=y m(Na2O)=31g m(Na2O2)=39g

    2.

    设Na2O2为xmol,Na2O为ymol Na2O-----2NaOH 2Na2O2---4NaOH---O2 1mol 2mol 2mol 4mol 1mol y 2ymol x 2x 1/2x m(O2)=1/2x*32g/mol m液=70g+98g-16x=(168-16x)g m(NaOH)=(2x+2y)*40g m(NaOH)/m液=50%化简得 62y+78x=70 88x+80y=84 x=0.5=y m(Na2O)=31g m(Na2O2)=39g