假设 C 处切线与水平夹角为 beta ,张力为 F .
F * cos(beta) = T * cos(alpha) .(1)
T * sin(alpha) - F * sin(beta) = 1/4 * G
====>
F * sin(beta) = T * sin(alpha) - 1/4 * G .(2)
(1)平方 + (2)平方 可得:
F^2 = ( T * cos(alpha)) ^2 + ( T * sin(alpha) - 1/4 * G )^2
另一方面,
T * sin(alpha) * 2 = G
代入,可解出 F